Solve this .. a?
A couple plans to have four children. Using a tree diagram, obtain the sample space. Then, find the probability that family has three boys first, then a girl. And I have four answers to choose from … 3.16 6.1 1.8 16.1
1 / 16. The tree diagram will have two nodes at the top: first child, first child. Under each child first "and" first girl "will have" second child "and" second 'girl, four nodes in the second. In each of the four nodes will have "third child" and "third girl" level for eight nodes on the third level. In each of the eight nodes, will have "boy room" and "fourth" girl of sixteen for the nodes at the fourth level. You will sixteen ways your tree diagram, and only one of the sixteen going child – child – boy – girl. This shows that the probability is 1 / 16. Note: the question were "three boys and a girl in any order", the answer would be 1 / 4 in place. (Because the three additional routes – girl – child – child – Child, boy – girl – boy – boy, child – boy – girl – boy – involve three boys and a girl. But since the order specified, there is only one matching route out of sixteen.)
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